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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: căn 4x^2-12x+9 = căn 9x^2-24x+16

Toán Lớp 9: căn 4x^2-12x+9 = căn 9x^2-24x+16

Comments ( 2 )

  1. Giải đáp:
    S={1,7/5}
    Lời giải và giải thích chi tiết: 
    \sqrt[4x^2-12x+9]=\sqrt[9x^2-24x+16] 
    ⇔ \sqrt[(2x)^2-2.2x.3+3^2]=\sqrt[(3x)^2-2.3x.4+4^2]
    ⇔ \sqrt[(2x-3)^2]=\sqrt[(3x-4)^2]
    ⇔ |2x-3|=|3x-4|
    ⇔ \(\left[ \begin{array}{l}2x-3=3x-4\\2x-3=-3x+4\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}-x=-1\\5x=7\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=1\\x=\dfrac75\end{array} \right.\) 
    Vậy S{=1,7/5}

  2. $\sqrt[]{4x^2-12x+9}=$ $\sqrt[]{9x^2-24x+16}$
    ⇔ $\sqrt[]{(2x-3)^2}=\sqrt[]{(3x-4)^2}$ 
    ⇔ $|2x-3|^{}=|3x-4|$ 
    ⇔ \(\left[ \begin{array}{l}2x-3=3x-4\\2x-3=4-3x\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}-x=-1\\5x=7\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=1\\x=\dfrac{7}{5}\end{array} \right.\) 
    -> S = {$1^{};\dfrac{7}{5}$}
    Chúc bạn học tốt !!!!!

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222-9+11+12:2*14+14 = ? ( )

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