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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: √(5-2 √5)- √2 Thu gọn ===-.

Home/ Toán Lớp 9: √(5-2 √5)- √2 Thu gọn ===-.

Toán Lớp 9: √(5-2 √5)- √2 Thu gọn ===-.

Tháng Bảy 11, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: √(5-2 √5)- √2
Thu gọn …………………………………..

Comments ( 2 )

  1. cattien
    cattien
    11 Tháng Bảy, 2022 at 6:25 chiều
    Reply
    $\sqrt[]{5-2\sqrt[]{6}}-\sqrt[]{2}$ 
    $=\sqrt[]{3-2\sqrt[]{3}.\sqrt[]{2}+2}-\sqrt[]{2}$   
    $=\sqrt[]{(\sqrt[]{3}-\sqrt[]{2})^2}-\sqrt[]{2}$   
    $=|\sqrt[]{3}-\sqrt[]{2}|-\sqrt[]{2}$  
    $=\sqrt[]{3}-\sqrt[]{2}-\sqrt[]{2}$ 
    $=\sqrt[]{3}-2\sqrt[]{2}$  
    => $\sqrt[]{5-2\sqrt[]{6}}-\sqrt[]{2} = \sqrt[]{3}-2\sqrt[]{2}$ 
     

  2. ngocle44
    ngocle44
    11 Tháng Bảy, 2022 at 6:25 chiều
    Reply
    $\sqrt[]{5-2\sqrt[]{6}}-\sqrt[]{2}$ 
    $=\sqrt[]{3-2\sqrt[]{3}.\sqrt[]{2}+2}-\sqrt[]{2}$ 
    $=\sqrt[]{(\sqrt[]{3}-\sqrt[]{2})^2}-\sqrt[]{2}$ 
    $=|\sqrt[]{3}-\sqrt[]{2}|-\sqrt[]{2}$
    $=\sqrt[]{3}-\sqrt[]{2}-\sqrt[]{2}$
    $=\sqrt[]{3}-2\sqrt[]{2}$
     

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222-9+11+12:2*14+14 = ? ( )

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