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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 2√27 + √(1-√3) ² – $\frac{4}{√3 + 1}$

Toán Lớp 9: 2√27 + √(1-√3) ² – $\frac{4}{√3 + 1}$

Comments ( 1 )

  1. Giải đáp:
    $5\sqrt{3}+1.$
    Lời giải và giải thích chi tiết:
    $2\sqrt{27}+\sqrt{(1-\sqrt{3})^2}-\dfrac{4}{\sqrt{3}+1}\\ =2\sqrt{9.3}+|1-\sqrt{3}|-\dfrac{4(\sqrt{3}-1)}{(\sqrt{3}+1)(\sqrt{3}-1)}\\ =6\sqrt{3}+\sqrt{3}-1-\dfrac{4(\sqrt{3}-1)}{3-1}\\ =7\sqrt{3}-1-\dfrac{4(\sqrt{3}-1)}{2}\\ =7\sqrt{3}-1-2(\sqrt{3}-1)\\ =7\sqrt{3}-1-2\sqrt{3}+2\\ =5\sqrt{3}+1.$

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222-9+11+12:2*14+14 = ? ( )