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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 1/3 căn (9+6v+v^2) +4v/3 +5 với v <= -3

Toán Lớp 9: 1/3 căn (9+6v+v^2) +4v/3 +5 với v <= -3

Comments ( 1 )

  1. Giải đáp:
    $v+4.$
    Lời giải và giải thích chi tiết:
    $\dfrac{1}{3}\sqrt{9+6v+v^2}+\dfrac{4v}{3}+5(v \le -3)\\ =\dfrac{1}{3}\sqrt{v^2+6v+9}+\dfrac{4v}{3}+5\\ =\dfrac{1}{3}\sqrt{(v+3)^2}+\dfrac{4v}{3}+5\\ =\dfrac{1}{3}|v+3|+\dfrac{4v}{3}+5\\ =-\dfrac{1}{3}(v+3)+\dfrac{4v}{3}+5(\text{Do }\le -3)\\ =-\dfrac{1}{3}v-1+\dfrac{4v}{3}+5\\ =v+4.$

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222-9+11+12:2*14+14 = ? ( )