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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm `x ∈Z` để `P ∈Z` `(2x-1)/(x+1)`

Toán Lớp 8: Tìm x ∈Z để P ∈Z
(2x-1)/(x+1)

Comments ( 2 )

  1. $\\P=\dfrac{2x-1}{x+1}(x\ne -1)\\=\dfrac{2x+2-3}{x+1}\\=\dfrac{2(x+1)-3}{x+1}\\=\dfrac{2(x+1)}{x+1}-\dfrac{3}{x+1}\\=2 – \dfrac{3}{x+1}$
    Để $P\in Z$
    $\Rightarrow 3\vdots x+1$
    =>x+1\in Ư (3)={1;-1;3;-3}
    =>x\in {0; -2; 2; -4} (Thỏa mãn)
    Vậy x\in {0;-2;2;-4} để $P\in Z$
     

  2. ĐK: $x\ne -1$
    $\dfrac{2x-1}{x+1}\\=\dfrac{2x+2-3}{x+1}\\=\dfrac{2(x+1)-3}{x+1}\\=2-\dfrac{3}{x+1}$
    Để $\dfrac{2x-1}{x+1}\in\Bbb Z$ thì $3\vdots x+1$ hay $x+1\in Ư(3)=\{\pm 1;\pm 3\}$
    Ta có bảng:
    $\begin{array}{|c|c|c|}\hline x+1&-3&-1&1&3\\\hline x&-4&-2&0&2\\\hline &TM&TM&TM&TM\\\hline\end{array}$
    Vậy $x\in\{-4;-2;0;2\}$ thì $\dfrac{2x-1}{x+1}\in\Bbb Z$ 

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222-9+11+12:2*14+14 = ? ( )