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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết: $x(2x-1)$$-$$(x-1)^{2}$$+(x-5)(3-x)=20$

Toán Lớp 8: Tìm x biết:
$x(2x-1)$$-$$(x-1)^{2}$$+(x-5)(3-x)=20$

Comments ( 2 )

  1. x(2x-1)-(x-1)^2+(x-5)(3-x)=20$\\$<=>2x^2-x-x^2+2x-1+3x-x^2-15+5x-20=0$\\$<=>(2x^2-x^2-x^2)+(-x+2x+3x+5x)+(-1-15-20)=0$\\$<=>9x-36=0$\\$<=>9x=36$\\$<=>x=36/9$\\$<=>x=4
    Vậy x=4

  2. Giải đáp+Lời giải và giải thích chi tiết:
    x(2x-1)-(x-1)^2+(x-5)(3-x)=20
    2x^2-x-(x^2-2x+1)-x^2-3x-15+5x=20
    2x^2-x-x^2+2x-1-x^2+3x-15-5x=20
    (2x^2-x^2-x^2)+(2x-x+3x+5x)-(1+15)=20
    9x-16=20
    9x=20+16
    9x=36
    x=36:9
    x=4
    Vậy x=4
    * HĐT số 2:(A-B)^2=A^2-2AB+B^2

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222-9+11+12:2*14+14 = ? ( )