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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x a)9$x^{2}$ (`x` +1) = (`x` +1) b)5$x^{2}$ -13`x` +6=0 c)5$x^{2}$ +11`x` +6=0 d)7$x^{2}$ -10`x` +3=0 e) 7$x^{2}$ +22`x` +3=0

Toán Lớp 8: Tìm x
a)9$x^{2}$ (x +1) = (x +1)
b)5$x^{2}$ -13x +6=0
c)5$x^{2}$ +11x +6=0
d)7$x^{2}$ -10x +3=0
e) 7$x^{2}$ +22x +3=0

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     a) 9x^2(x+1)=(x+1)
    <=>9x^2(x+1)-(x+1)=0
    <=>(x+1)(9x^2-1)=0
    <=>(x+1)(3x-1)(3x+1)=0
    <=>$\left[\begin{matrix} x+1=0\\ 3x-1=0\\3x+1=0\end{matrix}\right.$
    <=>$\left[\begin{matrix} x=-1\\ x=\dfrac{1}{3}\\x=\dfrac{-1}{3}\end{matrix}\right.$
     Vậy x=-1 hoặc x=1/3 hoặc x=-1/3
     b) 5^2-13x+6=0
    <=>5x^2-10x-3x+6=0
    <=>5x(x-2)-3(x-2)=0
    <=>(x-2)(5x-3)=0
    <=>$\left[\begin{matrix} x-2=0\\ 5x-3=0\end{matrix}\right.$
    <=>$\left[\begin{matrix} x=2\\ x=\dfrac{3}{5}\end{matrix}\right.$
     Vậy x=2 hoăc =3/5
     c) 7x^2-10x+3=0
    <=>7x^2-7x-3x+3=0
    <=>7x(x-1)-3(x-1)=0
    <=>(x-1)(7x-3)=0
    <=>$\left[\begin{matrix} x-1=0\\ 7x-3=0\end{matrix}\right.$
    <=>$\left[\begin{matrix} x=1\\ x=\dfrac{3}{7}\end{matrix}\right.$
     Vậy x=1 hoặc x=3/7
     d) 7x^2+22x+3=0
    <=>7x^2+x+21x+3=0
    <=>x(7x+1)+3(7x+1)=0
    <=>(7x+1)(x+3)=0
    <=>$\left[\begin{matrix} 7x+1=0\\ x+3=0\end{matrix}\right.$
    <=>$\left[\begin{matrix} x=\dfrac{-1}{7}\\ x=-3\end{matrix}\right.$
     Vậy x=-1/7 hoặc x=-3

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222-9+11+12:2*14+14 = ? ( )

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