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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x a)(5x-1)(x+1)-2(x+3)^2=3x(x+7) b) 2(x-3)^2+(x-3)(x+3)=(x-4)^2 c) -5(x+3)^2+(x-1)(x+1)+(3-2x)^2 làm nhanh nha

Toán Lớp 8: Tìm x
a)(5x-1)(x+1)-2(x+3)^2=3x(x+7)
b) 2(x-3)^2+(x-3)(x+3)=(x-4)^2
c) -5(x+3)^2+(x-1)(x+1)+(3-2x)^2
làm nhanh nha

Comments ( 2 )

  1. Giải đáp: Bạn xem hình ~
     
    Lời giải và giải thích chi tiết:
     

    toan-lop-8-tim-a-5-1-1-2-3-2-3-7-b-2-3-2-3-3-4-2-c-5-3-2-1-1-3-2-2-lam-nhanh-nha

  2. a)
    (5x-1)(x+1) – 2 (x+3)^2 = 3x (x+7)
    => (5x . x + 5x . 1 – 1 . x  -1 . 1) – 2 (x^2 + 2 . x . 3 + 3^2) = 3x . x + 3x . 7
    => (5x^2 + 5x – x – 1) – 2 (x^2 + 6x + 9) = 3x^2 + 21x
    => 5x^2 + 5x – x – 1 – 2x^2 – 12x – 18 = 3x^2 + 21x
    => 5x^2 + 5x – x – 1 – 2x^2 – 12x – 18 – 3x^2 – 21x =0
    => (5x^2 – 2x^2 – 3x^2) + (5x – x – 12x – 21x) – (1+18) = 0
    => -29x – 19 = 0
    => -29x = 19
    => x = -19/29
    Vậy x=-19/29
    b)
    2 (x-3)^2 – (x-3)(x+3) = (x-4)^2
    => 2 (x^2 – 2 . x . 3 + 3^2) – (x^2 – 3^2) = x^2 – 2 . x . 4 + 4^2
    => 2 (x^2 – 6x + 9) – (x^2 – 9) = x^2 – 8x + 16
    => 2x^2 – 12x + 18 – x^2 + 9 = x^2 – 8x + 16
    => 2x^2 – 12x + 18 – x^2 + 9 – x^2 + 8x – 16 =0
    => (2x^2 – x^2 – x^2) + (8x – 12x) + (18+ 9-16) = 0
    =>  – 4x + 11 =0
    => -4x = -11
    => x = 11/4
    Vậy x=11/4
    c)
    -5 (x+3)^2 + (x-1)(x+1) = (3-2x)^2
    => -5 (x^2 + 2 . x . 3 + 3^2) + (x^2 – 1) = 3^2 – 2 . 3 . 2x + (2x)^2
    => -5 (x^2 + 6x + 9) + (x^2 – 1) = 9 – 12x + 4x^2
    => -5x^2 – 30x – 45 + x^2 – 1 = 9 – 12x + 4x^2
    => -5x^2 – 30x – 45 + x^2 – 1 – 9 + 12x – 4x^2 = 0
    => (-5x^2 + x^2 – 4x^2) + (12x – 30x) – (1+9+45) = 0
    => -8x^2 -18x – 55=0
    => 8x^2 + 18x + 55 = 0
    => 8 (x^2 + 9/4x + 81/64) + 359/8 =0
    => 8 [ x^2 + 2 . x . 9/8 + (9/8)^2] + 359/8 =0
    => 8 (x+9/8)^2 + 359/8 = 0 (không xảy ra)
    Vậy không tìm được x thỏa mãn yêu cầu đề bài.

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222-9+11+12:2*14+14 = ? ( )