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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: thực hiện phép tính cộng trừ phân thức $\frac{a^2}{a+1}$ + $\frac{1}{a-1}$ – $\frac{2a}{a^2-1}$

Toán Lớp 8: thực hiện phép tính cộng trừ phân thức
$\frac{a^2}{a+1}$ + $\frac{1}{a-1}$ – $\frac{2a}{a^2-1}$

Comments ( 2 )

  1. (a^2)/(a+1)+1/(a-1) – (2a)/(a^2 -1)
    = ( a^2(a-1) )/( (a+1)(a-1)) + (a+1)/( (a-1)(a+1)) – (2a)/((a-1)(a+1))
    = (a^3 -a^2)/((a-1)(a+1)) + (a+1)/((a-1)(a+1)) – (2a)/((a-1)(a+1))
    = (a^3 – a^2 + a +1 – 2a)/((a-1)(a+1))
    = ( a^3 -a^2 – a + 1)/((a-1)(a+1))
    = ( a^2(a -1) – (a – 1))/((a-1)(a+1))
    = ( (a^2 -1)(a-1) )/((a-1)(a+1)) 
    = ( (a-1)(a+1)(a-1) )/((a-1)(a+1)) 
    = a-1 
     

  2. $\dfrac{a²}{a + 1}$ + $\dfrac{1}{a – 1}$ – $\dfrac{2a}{a² – 1}$ Đkxđ: a $\neq$ ±1
    = $\dfrac{a².(a – 1) + 1.(a + 1) – 2a}{(a – 1)(a + 1)}$
    = $\dfrac{a³ – a² + a + 1 – 2a}{(a – 1)(a + 1)}$
    = $\dfrac{a³ – a² – a + 1}{(a – 1)(a + 1)}$  
    = $\dfrac{(a³ – a) – (a² – 1)}{(a – 1)(a + 1)}$
    = $\dfrac{a(a² – 1) – (a² – 1)}{(a – 1)(a + 1)}$
    = $\dfrac{(a² – 1)(a – 1)}{a² – 1}$
    = a – 1
    Chúc bạn học tốt
     

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222-9+11+12:2*14+14 = ? ( )