Toán Lớp 8: Thực hiện phép tính 2x-ax. y+2
———– ——–
2ay+4a x
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: Thực hiện phép tính 2x-ax. y+2
———– ——–
2ay+4a x
Comments ( 2 )
(2x-ax)/(2ay+4a).(y+2)/(x)
=[x(2-a)]/[2a(y+2)].(y+2)/(x)
=(2-a)/(2a)
$\dfrac{2x-ax}{2ay+4a}\cdot \dfrac{y+2}{x}$ $;$ ( x!=0 ; a y + 2 a!=0)
$=\dfrac{\left(2x-ax\right)\left(y+2\right)}{\left(2ay+4a\right)x}$
$=\dfrac{x\left(2-a\right)\left(y+2\right)}{\left(2ay+4a\right)x}$
$=\dfrac{\left(2-a\right)\left(y+2\right)}{2ay+4a}$
$=\dfrac{\left(2-a\right)\left(y+2\right)}{2a\left(y+2\right)}$
$=\dfrac{2-a}{2a}$