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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: thức hiện phép tính 1/2x+3-1/2x-3+x-2/2x^2-x-3

Tháng Sáu 1, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: thức hiện phép tính 1/2x+3-1/2x-3+x-2/2x^2-x-3

Comments ( 1 )

  1. khanhngantoan
    khanhngantoan
    1 Tháng Sáu, 2022 at 6:10 sáng
    Reply
    1/(2x+3) – 1/(2x-3) + (x-2)/(2x^2 -x-3)
    = 1/(2x+3) – 1/(2x-3) + (x-2)/[(x+1)(2x-3)]
    = [(2x-3)(x+1)]/[(x+1)(2x+3)(2x-3)] – [(x+1)(2x+3)]/[(x+1)(2x+3)(2x-3)] + [(x-2)(2x+3)]/[(x+1)(2x+3)(2x-3)]
     = (2x^2 +2x-3x-3)/[(x+1)(2x+3)(2x-3)] – (2x^2 + 3x+2x+3)/[(x+1)(2x+3)(2x-3)] + (2x^2 + 3x – 4x-6)/[(x+1)(2x+3)(2x-3)]
    = (2x^2-x-3)/[(x+1)(2x+3)(2x-3)] – (2x^2 +5x+3)/[(x+1)(2x+3)(2x-3)] + (2x^2 -x -6)/[(x+1)(2x+3)(2x-3)]
    = (2x^2-x-3 – 2x^2 – 5x -3 + 2x^2 -x-6)/[(x+1)(2x+3)(2x-3)]
    = (2x^2 -7x -12)/[(x+1)(2x+3)(2x-3)]

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222-9+11+12:2*14+14 = ? ( )

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