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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn phép tính ( 1/x mũ 2 + 4x + 4 – 1/ x mũ 2 – 4x +4) : ( 1/x +2+1/x-2 )có kết quả bằng

Toán Lớp 8: Rút gọn phép tính ( 1/x mũ 2 + 4x + 4 – 1/ x mũ 2 – 4x +4) : ( 1/x +2+1/x-2 )có kết quả bằng

Comments ( 2 )

  1. $\left(\frac{1}{x^2+\:4x\:+\:4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x\:+2}+\frac{1}{x-2}\right)$
    $=-\frac{8x}{\left(x+2\right)^2\left(x-2\right)^2}:\frac{1}{x+2}+\frac{1}{x-2}$
    $=-\frac{8x}{\left(x+2\right)^2\left(x-2\right)^2}:\frac{2x}{\left(x+2\right)\left(x-2\right)}$
    $=-\frac{\frac{8x}{\left(x+2\right)^2\left(x-2\right)^2}}{\frac{2x}{\left(x+2\right)\left(x-2\right)}}$
    $=-\frac{8x\left(x+2\right)\left(x-2\right)}{\left(x+2\right)^2\left(x-2\right)^2\cdot \:2x}$
    $=-\frac{4}{\left(x+2\right)\left(x-2\right)}$

  2. Giải đáp:
     $(\dfrac{1}{x²+4x+4}-\dfrac{1}{x²-4x+4}):(\dfrac{1}{x+2}+\dfrac{1}{x-2})$
    $= (\dfrac{1.(x²-4x+4)}{(x²+4x+4).(x²-4x+4)}-\dfrac{1.(x²+4x+4)}{(x²+4x+4).(x²-4x+4)}):(\dfrac{1.(x-2)}{(x-2).(x+2)}+\dfrac{1.(x+2)}{(x-2).(x+2)})$
    $= (\dfrac{x²-4x+4-x²-4x-4}{(x²+4x+4).(x²-4x+4)}):(\dfrac{x-2+x+2}{(x-2).(x+2)}$
    $= \dfrac{-8x}{(x²+4x+4).(x²-4x+4)}:\dfrac{2x}{(x-2).(x+2)}$
    $= \dfrac{-8x}{(x+2)².(x-2)²}.\dfrac{(x-2).(x+2)}{2x}$
    $= \dfrac{-4}{(x-2).(x+2)}$
     

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222-9+11+12:2*14+14 = ? ( )