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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: rút gọn các câu sau bằng cách sử dụng hằng đẳng thức a) (3x-2)^2+(2x+5)^2-(3x+4).(3x-4) b) (3x+2).(9x^2 – 6x+4) + (5-3x).(25+15+9x^2)

Toán Lớp 8: rút gọn các câu sau bằng cách sử dụng hằng đẳng thức
a) (3x-2)^2+(2x+5)^2-(3x+4).(3x-4)
b) (3x+2).(9x^2 – 6x+4) + (5-3x).(25+15+9x^2)-9
c) (x-3)^3 – (x+2).(x-2).(x-1)

Comments ( 2 )

  1. #Sad
    a)
    (3x-2)^2+(2x+5)^2-(3x+4)(3x-4)
    = 9x^2-12x+4+4x^2+20x+25-9x^2+16
    = (9x^2+4x^2-9x^2)+(-12x+20x)+(4+25+16)
    = 4x^2+8x+45
    b)
    (3x+2)(9x^2-6x+4)+(5-3x)(25+15x+9x^2)-9
    = 27x^3+8+125-27x^3-9
    = (27x^3-27x^3)+(8+125-9)
    = 124
    c)
    (x-3)^3-(x+2)(x-2)(x-1)
    = x^3-9x^2+27x-27-(x^2-4)(x-1)
    = x^3-9x^2+27x-27-x^3+x^2+4x-4
    = (x^3-x^3)+(-9x^2+x^2)+(27x+4x)+(-27-4)
    = -8x^2+31x-31
     

  2. Giải đáp:
    a) (3x-2)²+(2x+5)²-(3x+4).(3x-4)
    =(3x-2)²+(2x+5)²- 9x²+16
    = 9x²-12x+4+4x²+20x+25-9x²+16
    = (9x²+4x²-9x²)+(-12x+20x)+(4+25+16)
    = 4x²+8x+45
    b) (3x+2).(9x² – 6x+4) + (5-3x).(25+15+9x²)-9
    =27????³−18????²+12????+18????²−12????+8+(5-3x)(40+9x²)-9
    =27????³−18????²+18????²+12????−12????+8+200+45????²-120x-27????³-9
    =(27????³-27????³)+(−18????²+18????²+45????²)+(12????−12????-120x)+(8+200-9)
    =45????²-120x+199
    c) (x-3)³ – (x+2).(x-2).(x-1)
    = (x-3)³ – (x²-4)(x-1)
    = x³-9x²+27x-27 – x³+x²+4x-4
    = (x³- x³)+(-9x²+x²)+(27x+4x)-(27+4)
    =-8x²+31x-31 

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222-9+11+12:2*14+14 = ? ( )

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