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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn `((x-1)^2/(3x+(x-1)^2)-(1-2x^2+4x)/(x^3-1)-1/(1-x)):(2x)/(x^3+x)`

Tháng Tư 13, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: Rút gọn ((x-1)^2/(3x+(x-1)^2)-(1-2x^2+4x)/(x^3-1)-1/(1-x)):(2x)/(x^3+x)

Comments ( 1 )

  1. lanminhngoc
    lanminhngoc
    13 Tháng Tư, 2022 at 3:44 chiều
    Reply
    $\text{($\dfrac{(x – 1)^{2}}{3x + (x – 1)^{2}}$ – $\dfrac{1 – 2x^{2} + 4x}{x^{3} – 1}$ – $\dfrac{1}{1 – x}$) : $\dfrac{2x}{x^{3} + x}$ Đkxđ: x $\neq$ 1; x $\neq$ 0}$
    $\text{= ($\dfrac{(x – 1)^{2}}{3x + x^{2} – 2x + 1}$ – $\dfrac{1 – 2x^{2} + 4x}{x^{3} – 1}$ + $\dfrac{1}{x – 1}$) . $\dfrac{x^{3} + x}{2x}$}$
    $\text{= $\dfrac{(x – 1)^{2} . (x – 1) – (1 – 2x^{2} + 4x) + 1.(x^{2} + x + 1)}{(x – 1)(x^{2} + x + 1)}$ . $\dfrac{x(x^{2} + 1)}{2x}$}$
    $\text{= $\dfrac{x^{3} – 3x^{2} + 3x – 1 – 1 + 2x^{2} – 4x + x^{2} + x + 1}{(x – 1)(x^{2} + x + 1)}$ . $\dfrac{x^{2} + 1}{2}$}$
    $\text{= $\dfrac{x^{3} – 1}{(x – 1)(x^{2} + x + 1)}$ . $\dfrac{x^{2} + 1}{2}$}$
    $\text{= $\dfrac{(x – 1)(x^{2} + x + 1)}{(x – 1)(x^{2} + x + 1)}$ . $\dfrac{x^{2} + 1}{2}$}$
    $\text{= $\dfrac{x^{2} + 1}{2}$ }$
    $\textit{Ha1zzz}$
     

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222-9+11+12:2*14+14 = ? ( )

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