Toán Lớp 8: phân tích nhân tử x^16 + x^8+1
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Toán Lớp 8: phân tích nhân tử x^16 + x^8+1
Comments ( 2 )
{x^{16}} + {x^8} + 1\\
= {\left( {{x^8}} \right)^2} + 2.{x^8}.1 + 1 – {x^8}\\
= {\left( {{x^8} + 1} \right)^2} – {x^8}\\
= {\left( {{x^8} + 1} \right)^2} – {\left( {{x^4}} \right)^2}\\
= \left( {{x^8} + 1 + {x^4}} \right)\left( {{x^8} – {x^4} + 1} \right)
\end{array}$
Mong đc hay nhất ạ
