Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải các bất phương trình sau: a) (x + 5)(7 – 2x) > 0 b) (2x + 1) (x – 3) < 0 c) x ² - 6x < 0 d) x ² - 4x + 3 >0

Toán Lớp 8: Giải các bất phương trình sau:
a) (x + 5)(7 – 2x) > 0
b) (2x + 1) (x – 3) < 0 c) x ² - 6x < 0 d) x ² - 4x + 3 >0

Comments ( 2 )

  1. a/ $(x+5)(7-2x) > 0$
    $⇔\left[ \begin{array}{l}\begin{cases}x+5>0\\7-2x>0\end{cases}\\\begin{cases}x+5<0\\7-2x<0\end{cases}\end{array} \right.$
    $⇔\left[ \begin{array}{l}\begin{cases}x>-5\\x<\dfrac72\end{cases}\\\begin{cases}x<-5\\x>\dfrac72\end{cases}\end{array} \right.$
    $⇔ -5 < x <\dfrac72$
    b/ $(2x+1)(x-3)=0$
    $⇔\left[ \begin{array}{l}\begin{cases}2x+1>0\\x-3<0\end{cases}\\\begin{cases}2x+1<0\\x-3>0\end{cases}\end{array} \right.$
    $⇔\left[ \begin{array}{l}\begin{cases}x>-\dfrac12\\x<3\end{cases}\\\begin{cases}x<-\dfrac12\\x>3\end{cases}\end{array} \right.$
    $⇔ -\dfrac12 < x < 3$
    c/ $x^2-6x < 0$
    $⇔ x(x-6) < 0$
    $⇔\left[ \begin{array}{l}\begin{cases}x>0\\x-6<0\end{cases}\\\begin{cases}x<0\\x-6>0\end{cases}\end{array} \right.$
    $⇔\left[ \begin{array}{l}\begin{cases}x>0\\x<6\end{cases}\\\begin{cases}x<0\\x>6\end{cases}\end{array} \right.$
    $⇔ 0 < x < 6$
    d/ $x^2-4x+3>0$
    $⇔ x(x-1)-3(x-1)>0$
    $⇔ (x-3)(x-1)>0$
    $⇔\left[ \begin{array}{l}\begin{cases}x-3>0\\x-1>0\end{cases}\\\begin{cases}x-3<0\\x-1<0\end{cases}\end{array} \right.$
    $⇔\left[ \begin{array}{l}\begin{cases}x>3\\x>1\end{cases}\\\begin{cases}x<3\\x<1\end{cases}\end{array} \right.$
    $⇔ 1 < x <3$

Leave a reply

222-9+11+12:2*14+14 = ? ( )

About Mai Lan