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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: $\frac{x^{2}-8x+7}{(7-x)(x+2)}$

Toán Lớp 8: $\frac{x^{2}-8x+7}{(7-x)(x+2)}$

Comments ( 2 )

  1. Gửi bạn:
    $ĐKXĐ:x\neq 7,-2$
    $\dfrac{x^2-8x+7}{(7-x)(x+2)}$ 
    $=\dfrac{x^2-x-7x+7}{(7-x)(x+2)}$ 
    $=\dfrac{x(x-1)-7(x-1)}{(7-x)(x+2)}$ 
    $=\dfrac{(x-1)(x-7)}{(7-x)(x+2)}$ 
    $=\dfrac{(x-1)[-(7-x)]}{(7-x)(x+2)}$ 
    $=\dfrac{-(x-1)(7-x)}{(7-x)(x+2)}$ 
    $=\dfrac{(1-x)(7-x)}{(7-x)(x+2)}$ 
    $=\dfrac{1-x}{x+2}$ 
     

  2. Giải đáp:
    = – {x – 1}/{x + 2}
    Lời giải và giải thích chi tiết:
     {x^2 – 8x + 7}/{(7 – x)(x + 2)}         (ĐKXĐ: x ne 7 ; x ne – 2)
    = {x^2 – 7x – x + 7}/{(7 – x)(x + 2)}
    = {(x^2 – 7x) – (x – 7)}/{(7 – x)(x + 2)}
    = {x(x – 7) – (x – 7)}/{(7 – x)(x + 2)}
    ={(x – 7)(x – 1)}/{(7 – x)(x + 2)}
    = {(x – 7)(x – 1)}/{- (x – 7)(x + 2)}
    = {x – 1}/{- (x + 2)}
    = – {x – 1}/{x + 2}
    #SunHee

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222-9+11+12:2*14+14 = ? ( )