Toán Lớp 8: ($\frac{x}{x^2-25}$-$\frac{x+5}{x^2-5x}$):$\frac{2x+5}{x^2-5x}$-$\frac{x}{x-5}$
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Toán Lớp 8: ($\frac{x}{x^2-25}$-$\frac{x+5}{x^2-5x}$):$\frac{2x+5}{x^2-5x}$-$\frac{x}{x-5}$
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$\left(\dfrac{x}{x^2-25}-\dfrac{x+5}{x^2-5x}\right):\dfrac{2x+5}{x^2-5x}-\dfrac{x}{x-5}$
$=\dfrac{-10x-25}{x\left(x+5\right)\left(x-5\right)}:\dfrac{2x+5}{x^2-5x}-\dfrac{x}{x-5}$
$=\dfrac{-10x-25}{x\left(x+5\right)\left(x-5\right)}:\dfrac{2x+5-x^2}{x\left(x-5\right)}$
$=\dfrac{\left(-10x-25\right)x\left(x-5\right)}{x\left(x+5\right)\left(x-5\right)\left(2x+5-x^2\right)}$
$=\dfrac{-10x-25}{\left(x+5\right)\left(2x+5-x^2\right)}$