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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: e)( x + 2)^2– ( x – 2 )( x + 2 ) = 0

Toán Lớp 8: e)( x + 2)^2– ( x – 2 )( x + 2 ) = 0

Comments ( 2 )

  1. $\text{- Ta có:}$
         $(x+2)^2-(x-2)(x+2)=0$
    ⇔ $(x+2)(x+2)-(x-2)(x+2)=0$
    ⇔ $(x+2)[(x+2)-(x-2)]=0$
    ⇔ $(x+2)(x+2-x+2)=0$
    ⇔ $(x+2).4=0$
    ⇔ $x+2=0$
    ⇔ $x=-2$
    $\text{- Vậy nghiệm của phương trình là $x=-2$ hay $S=\{-2\}$.}$

  2. Giải đáp:
    e)( x + 2)^2– ( x – 2 )( x + 2 ) = 0
    => (x+2)(x+2)-(x-2)(x+2)=0
    => (x+2).[(x+2)-(x-2)]=0
    => (x+2). (x+2-x+2)=0
    => (x+2). 4=0
    => x+2=0
    => x=-2
    Vậy x=-2

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222-9+11+12:2*14+14 = ? ( )