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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a) y^3+4y^2+4y-x^2 y b)x^2 (x-2)+(4x-3)(2-x)

Toán Lớp 8: a) y^3+4y^2+4y-x^2 y
b)x^2 (x-2)+(4x-3)(2-x)

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     $a, y^{3}+4y^{2}+4y-x^{2}y$
    $=y.(y^{2}+4y+4-x^{2}$
    $=y.[(y+2)^{2}-x^{2}]$
    $=y.(y+2-x)(y+2+x)$
    $b, x^{2}.(x-2)+(4x-3)(2-x)$
    $=x^{2}(x-2)-(4x-3)(x-2)$
    $=(x-2)(x^{2}-4x+3)$

  2. a)y^3+4y^2+4y-x^2y
    =y(y^2+4y+4-x^2)
    =y[(y+2)^2-x^2]
    =y(y+2-x)(y+2+x)
    b)x^2(x-2)+(4x-3)(2-x)
    =x^2(x-2)-(4x-3)(x-2)
    =(x-2)(x^2-4x+3)

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222-9+11+12:2*14+14 = ? ( )

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