Toán Lớp 8: (x^5 + x^3 + x^2 + 1):(x^3 + 1)- x(x -1)
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Toán Lớp 8: (x^5 + x^3 + x^2 + 1):(x^3 + 1)- x(x -1)
Comments ( 2 )
Giải đáp:
= x + 1
Lời giải và giải thích chi tiết:
(x^5 + x^3 + x^2 + 1) : (x^3 + 1) – x(x – 1)
= [(x^5 + x^3) + (x^2 + 1)] : (x^3 + 1) – x(x – 1)
= [x^3 (x^2 + 1) + (x^2 + 1)] : (x^3 + 1) – x(x – 1)
= (x^2 + 1)(x^3 + 1) : (x^3 + 1) – x(x – 1)
= x^2 + 1 – x^2 + x
= (x^2 – x^2) + x + 1
= x + 1
#SunHee
(x^5 + x^3 + x^2 + 1):(x^3 + 1)- x(x -1)
=[(x^5 + x^3)+(x^2 + 1)]:(x^3+1)-x(x-1)
=[x^3(x^2+1)+(x^2 + 1)]:(x^3+1)-x(x-1)
=(x^2+1).(x^3+1):(x^3+1)-x^2+x
=x^2+1-x^2+x
=x+1