Toán Lớp 8: 40đ:V
$\dfrac{5x+\dfrac{3x-4}{5}}{15}$=$\dfrac{\dfrac{3-x}{15}+7x}{5}+1-x$
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Toán Lớp 8: 40đ:V
$\dfrac{5x+\dfrac{3x-4}{5}}{15}$=$\dfrac{\dfrac{3-x}{15}+7x}{5}+1-x$
Comments ( 1 )
Giải đáp+Lời giải và giải thích chi tiết:
$\frac{5x+\frac{3x-4}{5}}{15}$=$\frac{\frac{3-x}{15}+7x}{5}$+1-x
⇔ $\frac{\frac{25x+3x-4}{5}}{15}$=$\frac{\frac{3-x+105x}{15}}{5}$+1-x
⇔ $\frac{\frac{28x-4}{5}}{15}$=$\frac{\frac{3+104x}{15}}{5}$+1-x
⇔ $\frac{28x-4}{75}$=$\frac{3+104x}{75}$+1-x
⇔ $\frac{28x-4}{75}$=$\frac{3+104x+75-75x}{75}$
⇔ 28x-4=3+104x+75-75x
⇔ 28x-4=29x+78
⇔ 28x-29x=78+4
⇔ -x=82
⇔ x=-82
Vậy x=-82
Cho mk xin hay nhất để lên hạng nha