Toán Lớp 8: x(3x + 2) + (x + 1)^2 – (2x – 5)(2x + 5) = 0

x (3x + 2) + (x + 1)² – (2x – 5) (2x + 5) = 0 => 3x² + 2x + x² + 2x + 1 - 4x² + 25 = 0 => 4x + 26 = 0 => 4x = -26 => x = -13/2 Vậy x = -13/2

~ Bạn tham khảo ~ x(3x + 2) + (x + 1)^2 - (2x - 5)(2x + 5) = 0 <=> 3x^2+2x+x^2+2x+1-4x^2+25=0 <=> 4x+26=0 <=> 4x=-26 <=> x=-13/2 Vậy x=-13/2

Toán Lớp 8: x(3x + 2) + (x + 1)^2 – (2x

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