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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 3x(x-1)+6(x-1)=0 Rút gọn (x+2)(x-2)-(x-3)(x+1)

Home/ Toán Lớp 8: 3x(x-1)+6(x-1)=0 Rút gọn (x+2)(x-2)-(x-3)(x+1)

Toán Lớp 8: 3x(x-1)+6(x-1)=0 Rút gọn (x+2)(x-2)-(x-3)(x+1)

Tháng Tư 19, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: 3x(x-1)+6(x-1)=0
Rút gọn (x+2)(x-2)-(x-3)(x+1)

Comments ( 2 )

  1. danvanthu
    danvanthu
    19 Tháng Tư, 2022 at 1:09 sáng
    Reply
    3x(x-1) + 6(x-1)=0
    (x-1)(3x+6)=0
    =>\(\left[ \begin{array}{l}x-1=0\\3x+6=0\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=1\\x=-2\end{array} \right.\) 
    \text{Vậy}    x ∈{1;-2}
    (x+2)(x-2) – (x-3)(x+1)
    = x^2 – 4 – (x^2 + x – 3x – 3)
    =x^2 – 4 -x^2 – x+3x+3
    =2x -1
    @Green

  2. ngoclanhoa
    ngoclanhoa
    19 Tháng Tư, 2022 at 1:08 sáng
    Reply
    Giải đáp:
    $* 3x.(x-1)+6.(x-1)=0$
    $⇔ (3x+6).(x-1)=0$
    $⇔$   \(\left[ \begin{array}{l}3x+6=0\\x-1=0\end{array} \right.\) ⇔  \(\left[ \begin{array}{l}3x=-6\\x=1\end{array} \right.\) ⇔  \(\left[ \begin{array}{l}x=-2\\x=1\end{array} \right.\) 
    $Vậy$ $x=-2$ $hoặc$ $x=1$
    $* (x+2).(x-2)-(x-3).(x+1)$
    $= x²-4-(x²+x-3x-3)$
    $= x²-4-x²+2x+3$
    $= (x²-x²)+(3-4)+2x$
    $= 2x-1$
    $@Jupiter$
     

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222-9+11+12:2*14+14 = ? ( )

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