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Toán Lớp 8: (2x+1-$\frac{1}{1-2x}$ ):($\frac{a}{a+b}$- $\frac{a^{2}}{a^{2}-b^{2}}$ )

Home/ Toán Lớp 8: (2x+1-$\frac{1}{1-2x}$ ):($\frac{a}{a+b}$- $\frac{a^{2}}{a^{2}-b^{2}}$ )

Toán Lớp 8: (2x+1-$\frac{1}{1-2x}$ ):($\frac{a}{a+b}$- $\frac{a^{2}}{a^{2}-b^{2}}$ )

Ái Hồng Tháng Mười 11, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: (2x+1-$\frac{1}{1-2x}$ ):($\frac{a}{a+b}$- $\frac{a^{2}}{a^{2}-b^{2}}$ )

Comments ( 1 )

hongocha12
11 Tháng Mười, 2022 at 5:26 sáng

Reply

( 2x + 1 – \frac{1}{1-2x} ) : ( \frac{a}{a+b} – \frac{a^2}{a^2-b^2} )

= \frac{ ( 2x + 1 ) ( 1 – 2x ) – 1 }{1 -2x } : \frac{a ( a – b ) – a^2 }{ ( a- b ) ( a + b )}

= \frac{1-4x^2-1}{1-2x} : \frac{a^2-ab-a^2}{( a- b ) ( a + b )}

= \frac{-4x^2}{1-2x} : \frac{-ab}{a^2 -b^2 }

= \frac{-4x^2}{1-2x} . \frac{a^2-b^2}{-ab}

= \frac{4a^2b^2-4a^2x^2}{2abx-ab}

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