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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (2x-1)(2x+1)-(2x-1)^2 (x+3)(x-5)+(x-4)^2

Toán Lớp 8: (2x-1)(2x+1)-(2x-1)^2
(x+3)(x-5)+(x-4)^2

Comments ( 2 )

  1. Giải đáp+ Lời giải và giải thích chi tiết:
    * $(2x-1)(2x+1) -(2x-1)^2$
    $=(2x-1)[(2x+1)-(2x-1)]$
    $=(2x-1)(2x+1-2x+1)$
    $=2(2x-1)$

     * $(x+3)(x-5)+(x-4)^2$
    $=(x+3)(x-5)+(x-4)(x-4)$
    $=(x+3-1)(x-5+1)+(x-4)(x-4)$
    $=(x+2)(x-4)+(x-4)(x-4)$
    $=(x-4)[(x+2)+(x-4)]$
    $=(x-4)(x+2+x-4)$
    $=(x-4)(2x-2)$
    $=2(x-4)(x-1)$

  2. @Bao
    (2x-1)(2x+1)-(2x-1)^2
    =(2x-1)(2x+1-(2x-1))
    =(2x-1)(2x+1-2x+1)
    =(2x-1).2
    (x+3)(x-5)+(x-4)^2
    =(x+3-1)(x-5+1)+(x-4)^2
    =(x+2).(x-4)+(x-4)^2
    =(x-4).(x+2+x-4)
    =(x-4).(2x-2)
    =(x-4).2.(x-1)
    Chúc bạn học tốt
     

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222-9+11+12:2*14+14 = ? ( )