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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1.Rút gọn A=(3a+1)²+(2-3a).(2+3a) B=(3x-1)²-(3x-2)² 2.Tìm x (2x+1)²-(x-1)²=0 3.Tính a) 95²= b) 85²=

Toán Lớp 8: 1.Rút gọn
A=(3a+1)²+(2-3a).(2+3a)
B=(3x-1)²-(3x-2)²
2.Tìm x
(2x+1)²-(x-1)²=0
3.Tính
a) 95²=
b) 85²=

Comments ( 1 )

  1. Hướng dẫn trả lời:
    1)
    a) A = (3a + 1)^2 + (2 – 3a).(2 + 3a)
    A = [(3a)^2 + 2.3a.1 + 1^2] + [2^2 – (3a)^2]
    A = (9a^2 + 6a + 1) + (4 – 9a^2)
    A = 9a^2 + 6a + 1 + 4 – 9a^2
    A = (9a^2 – 9a^2) + 6a + (1 + 4)
    A = 6a + 5
    Giải thích:
    – Áp dụng HĐT (A + B)^2 = A^2 + 2AB + B^2 và HĐT A^2 – B^2 = (A + B).(A – B)
    b) B = (3x – 1)^2 – (3x – 2)^2
    B = [(3x – 1) + (3x – 2)].[(3x – 1) – (3x – 2)]
    B = (3x – 1 + 3x – 2).(3x – 1 – 3x + 2)
    B = [(3x + 3x) + (- 1 – 2)].[(3x – 3x) + (- 1 + 2)]
    B = (6x – 3).1
    B = 6x – 3
    Giải thích:
    – Áp dụng HĐT A^2 – B^2 = (A + B).(A – B)
    2)
    (2x + 1)^2 – (x – 1)^2 = 0
    → [(2x + 1) + (x – 1)].[(2x + 1) – (x – 1)] = 0
    → (2x + 1 + x – 1).(2x + 1 – x + 1) = 0
    → [(2x + x) + (1 – 1)].[(2x – x) (+ 1 + 1)] = 0
    → 3x.(x + 2) = 0
    → \(\left[ \begin{array}{l}3x = 0.\\x + 2 = 0.\end{array} \right.\)
    → \(\left[ \begin{array}{l}x = 0.\\x = -2.\end{array} \right.\)
    Vậy x = 0 hoặc x = -2.
    Giải thích:
    – Áp dụng HĐT A^2 – B^2 = (A + B).(A – B)
    3)
    a) 95^2.
    = (100 – 5)^2
    = 100^2 – 2.100.5 + 5^2
    = 10000 – 1000 + 25
    = 9025
    b) 85
    = (100 – 15)^2
    = 100^2 – 2.100.15 + 15^2
    = 10000 – 3000 + 225
    = 7225
    Giải thích:
    – Áp dụng HĐT (A – B)^2 = A^2 – 2AB + B^2

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222-9+11+12:2*14+14 = ? ( )