Toán Lớp 7: tính nhanh
$\sqrt{3^2 + 4^2}$ – $\sqrt{1^3 + 2^3 + 3^3}$
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Toán Lớp 7: tính nhanh
$\sqrt{3^2 + 4^2}$ – $\sqrt{1^3 + 2^3 + 3^3}$
Comments ( 2 )
= $\sqrt[]{9+16}$ – $\sqrt[]{36}$
= $\sqrt[]{25}$ – $\sqrt[]{36}$
= 5 – 6
= -1