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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tính: `a, (27^2 . 8^5)/(6^6 . 32^3) + (3^4 . 4^4)/(2^2 . 6^2)` `b, (4^5 . 9^4 – 2. 6^9)/(2^10 . 3^8 + 6^8 . 20)`

Toán Lớp 7: Tính:
a, (27^2 . 8^5)/(6^6 . 32^3) + (3^4 . 4^4)/(2^2 . 6^2)
b, (4^5 . 9^4 – 2. 6^9)/(2^10 . 3^8 + 6^8 . 20)

Comments ( 2 )

  1. Lời giải và giải thích chi tiết:
    Tính:
    a)
    (27^2 . 8^5)/(6^6 . 32^3)+(3^4 . 4^4)/(2^2 . 6^2)
    =((3^3)^2 . (2^3)^5)/((2.3)^6 . (2^5)^3)+(3^4 . (2^2)^4)/(2^2 . (2.3)^2)
    =(3^6 . 2^15)/(2^6 . 3^6 . 2^15)+(3^4 . 2^8)/(2^2 . 2^2 . 3^2)
    =(3^6 . 2^15)/(2^21 . 3^6)+(3^4 . 2^8)/(2^4 . 3^2)
    =(1.1)/(2^6 . 1)+(3^2 . 2^4)/(1.1)
    =1/64+3^2 . 2^4
    =1/64+9.16
    =1/64+144
    =1/64+9216/64
    =9217/64
    b)
    (4^5 . 9^4-2.6^9)/(2^10 . 3^8+6^8 . 20)
    =((2^2)^5 . (3^2)^4-2.(2.3)^9)/(2^10 . 3^8 + (2.3)^8 . 2^2 . 5)
    =(2^10 . 3^8 – 2. 2^9 . 3^9)/(2^10 . 3^8 + 2^8 . 3^8 . 2^2 . 5)
    =(2^10 . 3^8 – 2^10 . 3^9)/(2^10 . 3^8+2^10 . 3^8 .5)
    =(2^10 . 3^8 .(1-3))/(2^10 . 3^8 . (1+5))
    =(2^10 . 3^8 . (-2))/(2^10 . 3^8 . 6)
    =(-1 . 2^11 . 3^8)/(6 . 3^8 . 2^10)
    =(-1 . 2 . 1)/(6 . 1 . 1)
    =-2/6
    =-1/3

  2. Giải đáp:
    a) $\dfrac{9217}{64}$
    b) $\dfrac{-1}3$
    Lời giải và giải thích chi tiết:
    $a)\,\dfrac{27^2.8^5}{6^6.32^3}+\dfrac{3^4.4^4}{2^2.6^2}\\=\dfrac{\left(3^3\right)^2.\left(2^3\right)^5}{2^6.3^6.\left(2^5\right)^3}+\dfrac{12^4}{12^2}\\=\dfrac{3^6.2^{15}}{2^6.3^6.2^{15}}+12^2\\=\dfrac{1}{2^6}+144\\=\dfrac{1}{64}+144\\=\dfrac{9217}{64}\\b)\,\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\\=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.2^9.3^9}{2^{10}.3^8+3^8.2^8.2^2.5}\\=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+3^8.2^{10}.5}\\=\dfrac{2^{10}.3^8.(1-3)}{2^{10}.3^8.(1+5)}\\=\dfrac{1-3}{1+5}\\=\dfrac{-1}3$

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222-9+11+12:2*14+14 = ? ( )