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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x, y, z biết: 7/3x = 2/16y = 19/6z ; 2x-y-z=-6

Toán Lớp 7: Tìm x, y, z biết: 7/3x = 2/16y = 19/6z ; 2x-y-z=-6

Comments ( 1 )

  1. Giải đáp:$x = \dfrac{{171}}{{496}};y = \dfrac{{399}}{{62}};z = \dfrac{{63}}{{248}}$
     
    Lời giải và giải thích chi tiết:
    $\begin{array}{l}
    \dfrac{7}{3}x = \dfrac{2}{{16}}y = \dfrac{{19}}{6}z\\
     \Leftrightarrow \dfrac{7}{3}x = \dfrac{1}{8}y = \dfrac{{19}}{6}z\\
     \Leftrightarrow \dfrac{{7x}}{{3.7.19}} = \dfrac{y}{{8.7.19}} = \dfrac{{19z}}{{6.7.19}}\\
     \Leftrightarrow \dfrac{x}{{57}} = \dfrac{y}{{1064}} = \dfrac{z}{{42}} = \dfrac{{2x}}{{114}}\\
     = \dfrac{{2x – y – z}}{{114 – 1064 – 42}} = \dfrac{{ – 6}}{{ – 992}} = \dfrac{3}{{496}}\\
     \Leftrightarrow \left\{ \begin{array}{l}
    x = \dfrac{3}{{496}}.57 = \dfrac{{171}}{{496}}\\
    y = \dfrac{3}{{496}}.1064 = \dfrac{{399}}{{62}}\\
    z = \dfrac{3}{{496}}.42 = \dfrac{{63}}{{248}}
    \end{array} \right.\\
    Vậy\,x = \dfrac{{171}}{{496}};y = \dfrac{{399}}{{62}};z = \dfrac{{63}}{{248}}
    \end{array}$

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222-9+11+12:2*14+14 = ? ( )

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