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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x,y thuộc Z : |x-1|+|y-2|= 2

Toán Lớp 7: Tìm x,y thuộc Z : |x-1|+|y-2|= 2

Comments ( 2 )

  1. Giải đáp:
    (x,y) \in {(3;2),(-1;2),(2;3),(2;1),(0;3),(0;1),(1;3),(1;1)}.
    Lời giải và giải thích chi tiết:
    |x-1|+|y-2|=2
    <=>|x-1|=2-|y-2|
    Vì |y-2|>=0=>2-|y-2|<=2
    =>|x-1|<=2
    Mà x in ZZ=>|x-1| in ZZ
    =>|x-1| in {0;1;2}
    *|x-1|=2
    =>[(x-1=2),(x-1=-2):}
    =>[(x=3),(x=-1):}(1)
    =>|y-2|=0
    =>y-2=0
    =>y=2(2)
    (1)(2)=>[({(x=3),(y=2):}),({(x=-1),(y=2):}):}
    *|x-1|=1
    =>[(x-1=1),(x-1=-1):}
    =>[(x=2),(x=0):}(3)
    =>|y-2|=1
    =>[(y-2=1),(y-2=-1):}
    =>[(y=3),(y=1):}(4)
    (3)(4)=>[({(x=2),(y=3):}),({(x=2),(y=1):}),({(x=0),(y=3):}),({(x=0),(y=1):}):}
    *|x-1|=0
    =>x-1=0
    =>x=1(5)
    =>|y-2|=1
    =>[(y-2=1),(y-2=-1):}
    =>[(y=3),(y=1):}(6)
    (5)(6)=>[({(x=1),(y=3):}),({(x=1),(y=1):}):}
    Vậy (x,y) \in {(3;2),(-1;2),(2;3),(2;1),(0;3),(0;1),(1;3),(1;1)}.

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222-9+11+12:2*14+14 = ? ( )

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