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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: $\frac{59-x}{41}$ + $\frac{57-x}{43}$ +$\frac{53-x}{47}$ + $\frac{51-x}{49}$ = -4 Tìm x

Toán Lớp 7: $\frac{59-x}{41}$ + $\frac{57-x}{43}$ +$\frac{53-x}{47}$ + $\frac{51-x}{49}$ = -4
Tìm x

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    ( 59 – x )/41 + ( 57 – x )/43 + ( 53 – x )/47 + ( 51 – x )/49 = -4
    => ( 59 – x )/41 + ( 57 – x )/43 + ( 53 – x )/47 + ( 51 – x )/49 + 4 = 0
    => ( ( 59 – x )/41 + 1 ) + ( ( 57 – x )/43 + 1 ) + ( ( 53 – x )/47 + 1 ) + ( ( 51 – x )/49 + 1 ) = 0
    => ( 100 – x )/41 + ( 100 – x )/43 + ( 100 – x )/47 + ( 100 – x )/49 = 0
    => ( 100 – x )( 1/41 + 1/43 + 1/47 + 1/49 ) = 0
    mà 1/41 + 1/43 + 1/47 + 1/49 > 0
    => 100 – x = 0
    => x = 100

  2. Giải đáp+Lời giải và giải thích chi tiết:
     (59-x)/41+(57-x)/43+(53-x)/47+(51-x)/49=-4
    =>(59-x)/41+1+(57-x)/43+1+(53-x)/47+1+(51-x)/49+1=-4+4
    =>(59-x+41)/41+(57-x+43)/43+(53-x+47)/47+(51-x+49)/49=0
    =>(100-x)/41+(100-x)/43+(100-x)/47+(100-x)/49=0
    =>(100-x)(1/41+1/43+1/47+1/49)=0
     Vì 1/41+1/43+1/47+1/49 ne 0
     =>100-x=0
    =>x=100
       Vậy x=100

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222-9+11+12:2*14+14 = ? ( )

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