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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: ($\frac{-47}{81}$ × $\frac{3}{997}$) ÷ $\frac{8}{997}$ + ( $\frac{-34}{81}$ + $\frac{3}{997}$ ) ÷ $\frac{8}{997}$

Toán Lớp 7: ($\frac{-47}{81}$ × $\frac{3}{997}$) ÷ $\frac{8}{997}$ + ( $\frac{-34}{81}$ + $\frac{3}{997}$ ) ÷ $\frac{8}{997}$

Comments ( 2 )

  1. #andy
    \[\begin{array}{l}
    \left( {\dfrac{{ – 47}}{{81}} – \dfrac{3}{{997}}} \right):\dfrac{8}{{997}} + \left( {\dfrac{{ – 34}}{{81}} + \dfrac{3}{{997}}} \right):\dfrac{8}{{997}}\\
     = \left( {\dfrac{{ – 47}}{{81}} – \dfrac{3}{{997}} + \dfrac{{ – 34}}{{81}} + \dfrac{3}{{997}}} \right):\dfrac{8}{{997}}\\
     = \left( {\dfrac{{ – 47}}{{81}} + \dfrac{{ – 34}}{{81}}} \right):\dfrac{8}{{997}}\\
     = \dfrac{{ – 47 – 34}}{{81}}:\dfrac{8}{{997}}\\
     = \dfrac{{ – 81}}{{81}} \times \dfrac{{997}}{8}\\
     =  – 1 \times \dfrac{{997}}{8}\\
     =  – \dfrac{{997}}{8}
    \end{array}\]
    *Xin phép sử đề, vì nếu dấu nhân thì không thể rút gọn*

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     $(\dfrac{-47}{81}.\dfrac{3}{997}):\dfrac{8}{997}+(\dfrac{-34}{81}+\dfrac{3}{997}):\dfrac{8}{997}$
    $=(\dfrac{-47}{81}.\dfrac{3}{997}-\dfrac{34}{81}+\dfrac{3}{997}):\dfrac{8}{997}$
    $=[\dfrac{3}{997}.(1-\dfrac{47}{*81})-\dfrac{34}{81}].\dfrac{997}{8}$
    $=[\dfrac{3}{997}.\dfrac{34}{81}-\dfrac{34}{81}].\dfrac{997}{8}$
    $=\dfrac{34}{81}.(\dfrac{3}{997}-1).\dfrac{997}{8}$
    $=\dfrac{34}{81}.\dfrac{-994}{997}.\dfrac{997}{8}$
    $=\dfrac{-8449}{162}$
    (Bài tham khảo)

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222-9+11+12:2*14+14 = ? ( )