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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: a, |2x-3|-1=0 b, 2.|3x-1/2|+5=6

Toán Lớp 7: a, |2x-3|-1=0
b, 2.|3x-1/2|+5=6

Comments ( 2 )

  1. Trình bày lời giải:
    a)
    |2x-3|-1=0
    =>|2x-3|=0+1
    =>|2x-3|=1
    =>[(2x-3=1),(2x-3=-1):}
    =>[(2x=1+3),(2x=-1+3):}
    =>[(2x=4),(2x=2):}
    =>[(x=4:2),(x=2:2):}
    =>[(x=2),(x=1):}
    Vậy x\in{2;1}
    b)
    2.|3x-1/2|+5=6
    =>2.|3x-1/2|=6-5
    =>2.|3x-1/2|=1
    =>|3x-1/2|=1:2
    =>|3x-1/2|=1/2
    =>[(3x-1/2=1/2),(3x-1/2=-1/2):}
    =>[(3x=1/2+1/2),(3x=-1/2+1/2):}
    =>[(3x=1),(3x=0):}
    =>[(x=1/3),(x=0):}
    Vậy x\in{1/3;0}

  2. Giải đáp:
     a, |2x – 3| – 1 = 0
        |2x – 3|       = 1
    ⇒\(\left[ \begin{array}{l}2x – 3 = 1\\2x – 3 = -1\end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}x = 2\\x = 1\end{array} \right.\) 
    Vậy x \in {2 ; 1}
    b, 2 . |3x – 1/2| + 5 = 6
       2 . | 3x – 1/2|       = 1
             |3x – 1/2|       = 1/2
    ⇒\(\left[ \begin{array}{l}3x – \frac{1}{2} = \frac{1}{2}\\3x – \frac{1}{2} = -\frac{1}{2}\end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}3x = 1\\3x  = 0\end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}x = \frac{1}{3}\\x = 0\end{array} \right.\) 
    Vậy x \in{ 1/3 ; 0}

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222-9+11+12:2*14+14 = ? ( )