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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: (4x ² – 3 ) . (2x ² – 9 ) = 0 help ;-;

Home/ Toán Lớp 7: (4x ² – 3 ) . (2x ² – 9 ) = 0 help ;-;

Toán Lớp 7: (4x ² – 3 ) . (2x ² – 9 ) = 0 help ;-;

Tháng Tư 19, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: (4x ² – 3 ) . (2x ² – 9 ) = 0
help ;-;

Comments ( 2 )

  1. cobelolen
    cobelolen
    19 Tháng Tư, 2022 at 6:47 sáng
    Reply
    Giải đáp:
    (4x^(2)-3).(2x^(2)-9)=0
    $⇒\left[\begin{matrix}4x²-3=0\\ 2x²-9=0\end{matrix}\right.$
    $⇒\left[\begin{matrix}4x²=3\\ 2x²=9\end{matrix}\right.$
    $⇒\left[\begin{matrix}x²=\dfrac{3}{4}\\ x²=\dfrac{9}{2}\end{matrix}\right.$
    $⇒\left[\begin{matrix}x=±\sqrt{\dfrac{3}{4}}\\ x=±\sqrt{\dfrac{9}{2}}\end{matrix}\right.$
    Vậy x∈{±\sqrt{3/4};±\sqrt{9/2}}

  2. hiennhi98
    hiennhi98
    19 Tháng Tư, 2022 at 6:46 sáng
    Reply
    Ta có :
    (4x^2 – 3) . (2x^2 – 9) = 0
    => $\left[\begin{matrix} 4x^2 – 3 =0 \\ 2x^2 – 9 = 0\end{matrix}\right.$
    => $\left[\begin{matrix} 4x^2 =0 + 3\\ 2x^2 = 0 + 9\end{matrix}\right.$
    => $\left[\begin{matrix} 4x^2 = 3 \\ 2x^2 = 9\end{matrix}\right.$
    => $\left[\begin{matrix} x^2 = 3 : 4\\ x^2 = 9 : 2\end{matrix}\right.$
    => $\left[\begin{matrix} x^2 = \frac{3}{4}\\ x^2 = \frac{9}{2}\end{matrix}\right.$
    => $\left[\begin{matrix} x^2 = \frac{\sqrt{3^2}}{2^2}\\ x^2 = \frac{3^2}{\sqrt{2^2}}\end{matrix}\right.$
    => $\left[\begin{matrix} x = \frac{\sqrt{3}}{2}\\ x = \frac{3}{\sqrt{2}}\end{matrix}\right.$
    Vậy x = \sqrt{3}/2 ; x = 3/\sqrt{2}

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222-9+11+12:2*14+14 = ? ( )

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