Toán Lớp 7: 2x^2-6
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Toán Lớp 7: 2x^2-6
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Comments ( 2 )
$⇒2(x^2-3)=0$
$⇒x^2-3=0$
$⇒x^2=3$
$⇒x^2=(±\sqrt{3})^2$
$⇒x=±\sqrt{3}$
Vậy x∈{±\sqrt{3}}