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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm số tự nhiên n sao cho 2n+3 chia hết cho n-1

Toán Lớp 6: Tìm số tự nhiên n sao cho 2n+3 chia hết cho n-1

Comments ( 2 )

  1. Ta có: 2n + 3 vdots n – 1
    ⇔ 2(n – 1) + 5  vdots n – 1
    ⇔ 5 vdots n – 1 (vì 2(n-1) vdots n – 1)
    ⇔ n – 1 ∈ Ư(5) = {±1;±5}
    ⇔ n ∈ {2; 0; 6; -4}
    Mà n ∈ N ⇒ n ∈ {2;0;6}
    Vậy n ∈ {2;0;6}

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222-9+11+12:2*14+14 = ? ( )

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