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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm số nguyên x,y thỏa mãn : b> xy – x + 3y – 3 = 5

Toán Lớp 6: tìm số nguyên x,y thỏa mãn : b> xy – x + 3y – 3 = 5

Comments ( 2 )

  1. Answer
    xy – x + 3y – 3 = 5
    => (xy + 3y) – (x + 3) = 5
    => y . (x + 3) – (x + 3) = 5
    => (y – 1) . (x + 3) = 5
    $\text{Vì}$ x , y \in ZZ $\text{nên}$ y – 1 , x + 3 \in ZZ
    => y – 1 , x + 3 \in Ư(5) = {+-1 ; +-5}
    $\text{Lập bảng giá trị:}
    $\begin{array}{|c|c|c|}\hline x + 3&1&5&-1&-5\\\hline y – 1&5&1&-5&-1\\\hline x&-2&2&-4&-8\\\hline y&6&2&-4&0\\\hline \text{Thử lại}&\text{TM}&\text{TM}&\text{TM}&\text{TM}\\\hline\end{array}$
    $\text{Vậy}$ (x , y) = (-2 , 6) ; (2 , 2) ; (-4 , -4) ; (-8 , 0)

  2. Lời giải chi tiết:
    xy-x+3y-3=5
    =>x(y-1)+3(y-1)=5
    =>(x+3).(y-1)=5
    TH1: {(x+3=1),(y-1=5):}=>{(x=-2),(y=6):}
    TH2: {(x+3=5),(y-1=1):}=>{(x=2),(y=2):}
    TH3: {(x+3=-1),(y-1=-5):}=>{(x=-4),(y=-4):}
    TH4: {(x+3=-5),(y-1=-1):}=>{(x=-8),(y=0):}
    Vậy (x,y)\in{(-2,6);(2,2);(-4,-4);(-8,0)}

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222-9+11+12:2*14+14 = ? ( )