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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm số nguyên x,y sao cho : a) (x+2)·(x−1)=0 b) (x−1)·(y+1)=0 c) (3−x)·(y+5)=0 d) x·(y−5)=0 Help me pls !

Tháng Chín 7, 2022 Toán học 2 Comments 0 views

Toán Lớp 6: Tìm số nguyên x,y sao cho :
a) (x+2)·(x−1)=0
b) (x−1)·(y+1)=0
c) (3−x)·(y+5)=0
d) x·(y−5)=0
Help me pls !

Comments ( 2 )

  1. lyly98
    lyly98
    7 Tháng Chín, 2022 at 12:06 sáng
    Reply
    $\#Lynn2007$
    a)(x+2).(x-1)=0
    <=> \(\left[ \begin{array}{l}x+2=0\\x-1=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=-2(TM)\\x=1(TM)\end{array} \right.\) 
    \text{Vậy:} x=-2 và x=1.
    b)(x-1).(y+1)=0
    <=>  \(\left[ \begin{array}{l}x-1=0\\y+1=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=1(TM)\\y=-1(TM)\end{array} \right.\) 
    \text{Vậy:} x=1 và y=-1.
    c)(3-x).(y+5)=0
    <=> \(\left[ \begin{array}{l}3-x=0\\y+5=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=3(TM)\\y=-5(TM)\end{array} \right.\) 
    \text{Vậy:} x=3 và y=-5.
    d)x.(y-5)=0
    <=> \(\left[ \begin{array}{l}x=0\\y-5=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0(TM)\\y=5(TM)\end{array} \right.\) 
    \text{Vậy:} x=0 và y=5.

  2. kimoanh34
    kimoanh34
    7 Tháng Chín, 2022 at 12:05 sáng
    Reply
    a)(x+2)(x-1)=0
    ⇒\(\left[ \begin{array}{l}x+2=0\\x-1=0\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}x=-2\\x=1\end{array} \right.\) 
    b)(x-1)(y+1)=0
    ⇒\(\left[ \begin{array}{l}x-1=0\\y+1=0\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}x=1\\y=-1\end{array} \right.\) 
    c)(3−x)·(y+5)=0
    ⇒\(\left[ \begin{array}{l}3-x=0\\y+5=0\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}3=x\\y=-5\end{array} \right.\)
    d)x·(y−5)=0
    ⇒\(\left[ \begin{array}{l}x=0\\y-5=0\end{array} \right.\)
    ⇒\(\left[ \begin{array}{l}x=0\\y=5\end{array} \right.\)
    Cho 5 sao và ctlhn nha :333

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222-9+11+12:2*14+14 = ? ( )

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