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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x ,biết : a ) (x – 5 ) (x-7)=0 b) 96 -3(x+1) =42 Tính hợp lí : a) 2^2 .25.17 +5.20.27 +10^2 .56 b)2^2.78+2^3.29-2^3 .7

Toán Lớp 6: Tìm x ,biết :
a ) (x – 5 ) (x-7)=0
b) 96 -3(x+1) =42
Tính hợp lí :
a) 2^2 .25.17 +5.20.27 +10^2 .56
b)2^2.78+2^3.29-2^3 .7

Comments ( 2 )

  1. Bài 1:
    a) (x-5)(x-7) =0
    => x -5 = 0 hoặc x-7=0
    +) x – 5 =0
    =>x = 0+5
    => x =5
    +)x-7=0
    => x = 0+7
    => x =7
    Vậy x \in{5;7}
    b) 96 – 3(x+1) = 42
    => 3(x+1) = 96 – 42
    => 3(x+1) = 54
    => x + 1 = 54 : 3
    => x +1 = 18
    => x = 18-1
    => x =17
    Vậy x=17
    Bài 2:
    a) 2^2 . 25 . 17 + 5 . 20 . 27 + 10^2 . 56
    = 100 . 17 + 100 . 27 + 100 . 56
    = 100 . (17 + 27 + 56)
    = 100 . 100
    = 100 00
    b) 2^2 . 78 + 2^3 . 29 – 2^3 . 7
    = 2^2 . 2 . 39 + 2^3 . 29 – 2^3 .7
    = 8 . 39 + 8 . 29 –  8 . 7
    = 8 .(39 + 29 -7)
    = 8 . 61
    = 488

  2. a ) (x – 5 ) (x-7)=0
    ⇔\(\left[ \begin{array}{l}x – 5=0\\x – 7=0\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}x =5\\x =7\end{array} \right.\)
    (Vì nếu 1 tích bằng 0 thì 1 trong 2 thừa số bằng 0,sợ bạn học lớp 6 nên không hiểu)
    b)96 -3(x+1) =42
    ⇔ 96-3x-3=42
    ⇔ -3x=42+3-96
    ⇔ -3x=-51
    ⇔ x=17
    a) 2² .25.17 +5.20.27 +10² .56
    =2².5².17+5.5.4.27+10².56
    =2².5².17+5².2².27+10².56
    =10².17+10².27+10².56
    =100.(17+27+56)
    =100.100
    =10000
    b)2².78+2³.29-2³ .7
    =2².2.39+2³.29-2³.7
    =2³(39+29-7)
    =8.61
    =488
     

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222-9+11+12:2*14+14 = ? ( )