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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm x a, ( 2600 + 6400 ) – 3x =1200 b, [ (6x – 39) : 7 ] .4 = 12

Toán Lớp 6: tìm x
a, ( 2600 + 6400 ) – 3x =1200 b, [ (6x – 39) : 7 ] .4 = 12

Comments ( 2 )

  1. a,( 2600 + 6400 ) – 3x =1200
    =>9000- 3x =1200
     =>– 3x =1200-9000
    =>-3x=-7800
    =>x=2600
    b,[ (6x – 39) : 7 ] .4 = 12
    =>(6x – 39) : 7 =3
    =>6x – 39=21
    =>6x=60
    =>x=10

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a,
    $( 2600 + 6400 ) – 3x =1200$
    $⇒9000-3x=1200$
    $⇒3x=9000-1200$
    $⇒3x=7800$
    $⇒x=7800:3$
    $⇒x=2600$
    Vậy $x=2600$
    b,
    $[(6x-39):7].4=12$
    $⇒(6x-39):7=12:4$
    $⇒(6x-39):7=3$
    $⇒6x-39=3.7$
    $⇒6x-39=21$
    $⇒6x=21+39$
    $⇒6x=60$
    $⇒x=10$
    Vậy $x=10$
     

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222-9+11+12:2*14+14 = ? ( )