Toán Lớp 6: Tìm x:
|(x+1)+(x+2)+(x+3)+…+(x+100)|=0
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Toán Lớp 6: Tìm x:
|(x+1)+(x+2)+(x+3)+…+(x+100)|=0
Comments ( 2 )
=>|x+1+x+2+x+3+…+x+100|=0
=>| \underbrace{(x+x+x+…+x)}_{\text{có 100 x }}+\underbrace{(1+2+3+…+100)}_{\text{Có (100-1):1+1=100(số hạng)}} |=0
=>|100x+[(100+1)xx100:2]|=0
=>|100x+101xx100:2|=0
=>|100x+10100:2|=0
=>|100x+5050|=0
=>100x+5050=0
=>100x=0-5050
=>100x=-5050
=>x=-5050:100
=>x=-50,5
Vậy x=-50,5