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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Chứng minh rằng: A=1+3+3^2+3^3+…+3^2021 chia hết cho 10

Toán Lớp 6: Chứng minh rằng: A=1+3+3^2+3^3+…+3^2021 chia hết cho 10

Comments ( 2 )

  1. A=1+3+3^2+3^3+………+3^2021 
    A=(1+3+3^2+3^3)+……….+(3^2018+3^2019+3^2020+3^2021)
    A=1.(1+3+3^2+3^3)+…………..+3^2018.(1+3+3^2+3^3)
    A=1.40+……………+3^2018. 40
    A=40.(1+…………+3^2018)
    Vì 40vdots10
    =>Avdots10

  2. ~ Bạn tham khảo ~
    A = 1+3+3^2+3^3+…..+3^2021
    A = (1+3+3^2) + (3^3+3^4+3^5)+….+(3^2019+3^2020+3^2021)
    A = 10 + 3^3 . (1+3+9) + ….. + 3^2019 + (1+3+9)
    A = 10 +3^3 . 10 + ….. + 3^2019 . 10
    A = 10 . ( 1+3^3+…+3^2019)
    Mà 10 vdots 10
    Vậy A vdots 10
    $#Vịt vàng$

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222-9+11+12:2*14+14 = ? ( )