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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: cho mình hỏi với a)E=2+2^2+2^3+2^4+…+2^100 b)F=1+3^1+3^2+3^3…3^100 g)G=5+

Toán Lớp 6: cho mình hỏi với
a)E=2+2^2+2^3+2^4+…+2^100 b)F=1+3^1+3^2+3^3…3^100
g)G=5+5^3+5^5+5^7+…5^99 h) (1+2+3+…+100).(65.111-13.15.37)

Comments ( 2 )

  1. a) E=2+2^2+2^3+2^4+………………….+2^100
    2E=2^2+2^3+2^4+2^5+………………….+2^101
    2E-E=(2^2+2^3+2^4+2^5+………………….+2^101)-(2+2^2+2^3+2^4+………………….+2^100)
    E=2^101-2
    b) F=1+3^1+3^2+3^3+…………………………..+3^100
    3F=3^1+3^2+3^3+3^4+…………………………+3^101
    3F-F=(3^1+3^2+3^3+3^4+…………………………+3^101)-(1+3^1+3^2+3^3+…………………………..+3^100)
    2F=3^101-1
    F=(3^101-1)/2
    g) G=5+5^3+5^5+5^7+………………+5^99
    5^2G=5^3+5^5+5^7+5^9+…………………….+5^101
    25G-G=(5^3+5^5+5^7+5^9+…………………….+5^101)-(5+5^3+5^5+5^7+………………+5^99)
    24G=5^101-5
    G=(5^101-5)/24
    h)(1+2+3+…………………..+100).(1^2+2^2+3^2+…………………….+100^2).(65.111-13.15.37)
    =(1+2+3+……………………+100).(1^2+2^2+3^2+…………………….+100^2).(7215-7215)
    =A.B.0
    =0
     

  2. Giải đáp:a,
    E=2 + 2^2 + 2^3+…..+ 2^100
    2E=2^2 + 263 + 2^4 + … + 2^ 101
    2E-A =(2^2+2^3+2^4+…+2^100)-(2^2+^3+…+2^100)
    E=2^101-2
    E=0^101
     h,(1+2+3+…+100).(1^2+2^2+3^2+…+10^2).(65.111-13.15.37)
    = (1+2+3+…+100).(1^2+2^2+3^2+…+10^2).(65.111-13.555)
    =(1+2+3+…+100).(1^2+2^2+3^2+…+10^2).(65.111-13.5.111)
    =(1+2+3+…+100).(1^2+2^2+3^2+…+10^2).[111- (65- 65)]
    =(1+2+3+…+100).(1^2+2^2+3^2+…+10^2). 0
    =0
    Lời giải và giải thích chi tiết:
    #anhminh9103
    hoidap247
    :3

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222-9+11+12:2*14+14 = ? ( )

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