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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Bài 1 : Tính các tổng sau : a ) A = 1.2 + 2.3 + 3.4 + … + 99.100 b ) B = 1.2 + 2.3 + 3.4 + … + n.(n+1) ( n ∈ N*)

Toán Lớp 6: Bài 1 : Tính các tổng sau :
a ) A = 1.2 + 2.3 + 3.4 + … + 99.100
b ) B = 1.2 + 2.3 + 3.4 + … + n.(n+1) ( n ∈ N*)

Comments ( 2 )

  1. a)
     A = 1.2+2.3+3.4+…+99.100
    3A = 1.2.3+2.3.3+3.4.3+…+99.100+3
    3A = 1.2 (3-0) +2.3(4-1)+3.4(5-2) +…+ 99.100( 101-98)
    3A = ( 1.2.3 + 2.3.4 + 3.4.5 + 99.100.101 ) -( 0.1.2 + 1.2.3 + 2.3.4 + ….+ 98.99.100)
    3A = 99.100.101 – 0.1.2
    3A = 999900 – 0
    3A = 999900
    A = 999900 : 3
    A = 333300
    B)(hình ảnh)
    CHÚC BẠN LÀM BÀI TỐT ^^

    toan-lop-6-bai-1-tinh-cac-tong-sau-a-a-1-2-2-3-3-4-99-100-b-b-1-2-2-3-3-4-n-n-1-n-n

  2. a) A = 1 . 2 + 2 . 3 + 3 . 4 + …. + 99 . 100
    3A = 1 . 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + …. + 99 . 100 . 3
    3A = 1 . 2 . 3 + 2 . 3 . ( 4 – 1 ) + 3 . 4 . ( 5 – 2 ) + …. + 99 . 100 . ( 101 – 98 )
    3A = 1 . 2 . 3 + 2 . 3 . 4 – 1 . 2 . 3 + 3 . 4 . 5 – 2 . 3 . 4 + …. + 99 . 100 . 101 – 98 . 99 . 100
    3A = 99 . 100 . 101
    A = 99 . 100 . 101 : 3
    A = 100 . 101 . 33
    A = 100 . 3333
    A = 333300
    Vậy , A = 333300 .
    b) B = 1 . 2 + 2 . 3 + 3 . 4 + …. + n . ( n + 1 )
    3B = 1 . 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + …. + n . ( n + 1 ) . 3
    3B = 1 . 2 . 3 + 2 . 3 . ( 4 – 1 ) + 3 . 4 . ( 5 – 2 ) + …. + n . ( n + 1 ) . [ ( n + 2 ) – ( n – 1 ) ]
    3B = 1 . 2 . 3 + 2 . 3 . 4 – 1 . 2 . 3 + 3 . 4 . 5 – 2 . 3 . 4 + …. + n . ( n + 1 ) . ( n + 2 ) – ( n – 1 ) . n . ( n + 1 )
    3B = n . ( n + 1 ) . ( n + 2 ) 
    B = ( n . ( n + 1 ) . ( n + 2 ) )/3
    Vậy , B = ( n . ( n + 1 ) . ( n + 2 ) )/3 .

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222-9+11+12:2*14+14 = ? ( )

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