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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a) 25 –3.(6 –x) = 22 b) [(2x –11):3 + 1].5 = 20 c) (25 -2x)3: 5 -32= 42 d)2.3x= 10.312+ 8.274 mn giúp mk nha???????????????? ctlhn nhưng phải

Toán Lớp 6: a) 25 –3.(6 –x) = 22
b) [(2x –11):3 + 1].5 = 20
c) (25 -2x)3: 5 -32= 42
d)2.3x= 10.312+ 8.274
mn giúp mk nha????????????????
ctlhn nhưng phải nhanh và đúng nha,vote đầy đủ,cảm ơn????????????????

Comments ( 2 )

  1. #andy
    \[\begin{array}{l}
    \begin{array}{*{20}{l}}
    {a){\rm{ }}25{\rm{ }}-3.\left( {6{\rm{ }}-x} \right){\rm{ }} = {\rm{ }}22}\\
    { \Leftrightarrow {\rm{ }}25 – 18 + 3x = 22}\\
    { \Leftrightarrow {\rm{ }}3x = 22 – 25 + 18}\\
    { \Leftrightarrow {\rm{ }}3x = 15}\\
    { \Leftrightarrow {\rm{ }}x = 15:3}\\
    { \Rightarrow {\rm{ }}x = 5}
    \end{array}\\
    \begin{array}{*{20}{l}}
    {b){\rm{ }}\left[ {\left( {2x{\rm{ }}-11} \right):3{\rm{ }} + {\rm{ }}1} \right].5{\rm{ }} = {\rm{ }}20}\\
    { \Leftrightarrow {\rm{ }}\left( {2x{\rm{ }} – {\rm{ }}11} \right){\rm{ }}:{\rm{ }}3{\rm{ }} + {\rm{ }}1 = {\rm{ }}20{\rm{ }}:{\rm{ }}5}\\
    { \Leftrightarrow {\rm{ }}\left( {2x{\rm{ }} – {\rm{ }}11} \right){\rm{ }}:{\rm{ }}3{\rm{ }} + {\rm{ }}1 = {\rm{ }}4}\\
    { \Leftrightarrow \;{\rm{ }}\left( {2x{\rm{ }} – {\rm{ }}11} \right){\rm{ }}:{\rm{ }}3 = {\rm{ }}4{\rm{ }} – {\rm{ }}1}\\
    { \Leftrightarrow {\rm{ }}\left( {2x{\rm{ }} – {\rm{ }}11} \right){\rm{ }}:{\rm{ }}3 = {\rm{ }}3}\\
    { \Leftrightarrow {\rm{ }}\;2x{\rm{ }} – {\rm{ }}11 = {\rm{ }}3{\rm{ }} \times {\rm{ }}3}\\
    { \Leftrightarrow {\rm{ }}2x{\rm{ }} – {\rm{ }}11{\rm{ }} = {\rm{ }}9}\\
    { \Leftrightarrow \;{\rm{ }}\;2x{\rm{ }} = {\rm{ }}9{\rm{ }} + {\rm{ }}11}\\
    { \Leftrightarrow {\rm{ }}\;2x{\rm{ }} = {\rm{ }}20}\\
    { \Leftrightarrow {\rm{ }}\;{\rm{ }}x{\rm{ }} = {\rm{ }}20{\rm{ }}:{\rm{ }}2}\\
    {\; \Rightarrow \;{\rm{ }}x{\rm{ }} = {\rm{ }}10}
    \end{array}\\
    \begin{array}{*{20}{l}}
    {c){\rm{ }}\left( {25{\rm{ }} – 2x} \right)3:{\rm{ }}5{\rm{ }} – 32 = {\rm{ }}42}\\
    { \Leftrightarrow {\rm{ }}\left( {25{\rm{ }} – 2x} \right)3:{\rm{ }}5{\rm{ }} = {\rm{ }}42 + 32}\\
    { \Leftrightarrow {\rm{ }}\left( {25{\rm{ }} – 2x} \right)3:{\rm{ }}5{\rm{ }} = {\rm{ }}74}\\
    { \Leftrightarrow {\rm{ }}\left( {25{\rm{ }} – 2x} \right)3\;{\rm{ }} = {\rm{ }}74{\rm{ }}.{\rm{ }}5}\\
    { \Leftrightarrow {\rm{ }}\left( {25{\rm{ }} – 2x} \right)3\;{\rm{ }} = {\rm{ }}370}\\
    { \Leftrightarrow {\rm{ }}75{\rm{ }} – {\rm{ }}6x{\rm{ }} = {\rm{ }}370}\\
    { \Leftrightarrow {\rm{ }} – 6x{\rm{ }} = {\rm{ }}370{\rm{ }} – {\rm{ }}75}\\
    { \Leftrightarrow {\rm{ }} – 6x{\rm{ }} = {\rm{ }}295}\\
    \begin{array}{l}
     \Leftrightarrow {\rm{ }} – x{\rm{ }} = {\rm{ }}295{\rm{ }}:{\rm{ }}6\\
     \Leftrightarrow  – x = \dfrac{{295}}{6}\\
     \Leftrightarrow x =  – \dfrac{{295}}{6}\\
    \begin{array}{*{20}{l}}
    {d)2.3x = {\rm{ }}10.312 + {\rm{ }}8.274}\\
    { \Leftrightarrow {\rm{ }}6x{\rm{ }} = {\rm{ }}3120{\rm{ }} + {\rm{ }}2192}\\
    { \Leftrightarrow {\rm{ }}6x{\rm{ }} = {\rm{ }}5312}\\
    { \Leftrightarrow {\rm{ }}x{\rm{ }} = {\rm{ }}5312{\rm{ }}:{\rm{ }}6}
    \end{array}
    \end{array}
    \end{array}\\
     \Leftrightarrow x = \dfrac{{2656}}{3}
    \end{array}\]

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a) 25 –3.(6 –x) = 22
    ⇔ 25-18+3x=22
    ⇔ 3x=22-25+18
    ⇔ 3x=15
    ⇔ x=15:3
    ⇒ x=5
    Vậy x=5
    b) [(2x –11):3 + 1].5 = 20
    ⇔ (2x – 11) : 3 + 1= 20 : 5
    ⇔ (2x – 11) : 3 + 1= 4
    ⇔  (2x – 11) : 3= 4 – 1
    ⇔ (2x – 11) : 3= 3
    ⇔  2x – 11= 3 × 3
    ⇔ 2x – 11 = 9
    ⇔   2x = 9 + 11
    ⇔  2x = 20
    ⇔   x = 20 : 2
      ⇒  x = 10
    Vậy x = 10
    c) (25 -2x)3: 5 -32= 42
    ⇔ (25 -2x)3: 5 = 42+32
    ⇔ (25 -2x)3: 5 = 74
    ⇔ (25 -2x)3  = 74 . 5
    ⇔ (25 -2x)3  = 370
    ⇔ 75 – 6x = 370
    ⇔ -6x = 370 – 75
    ⇔ -6x = 295
    ⇔ -x = 295 : 6
    ⇔ -x = $\frac{295}{6}$ 
    ⇒ x = – $\frac{295}{6}$
    Vậy x = – $\frac{295}{6}$
    d)2.3x= 10.312+ 8.274
    ⇔ 6x = 3120 + 2192
    ⇔ 6x = 5312
    ⇔ x = 5312 : 6
    ⇒ x = $\frac{2656}{3}$ 
    Vậy x = $\frac{2656}{3}$

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