Toán Lớp 6: $9^{x+2}$ x $3^{5}$ = ($9^{3}$ $)^{7}$
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Toán Lớp 6: $9^{x+2}$ x $3^{5}$ = ($9^{3}$ $)^{7}$
Comments ( 2 )
=$9^{x+2}$ x $3^{5}$ = $9^{21}$
=$9^{x+2}$ x $3^{5}$ = ($3^{2}$)$^{21}$
=$9^{x+2}$ x $3^{5}$ = $3^{42}$
=$9^{x+2}$=$3^{42}$ : $3^{5}$
=$9^{x+2}$=$3^{37}$
=[($3^{2}$)$^{x+2}$]=$3^{37}$
=$3^{2(x+2)}$ =$3^{37}$
=> 2(x+2)=37
x+2=37:2
x+2=18,5
x=18,5-2
x=16,5