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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: x.(x + 7) = 0 (x + 12).(x – 3) = 0 (-x + 5).(3 – x ) = 0 x.(2 + x) + 3x = 0

Toán Lớp 6: x.(x + 7) = 0
(x + 12).(x – 3) = 0
(-x + 5).(3 – x ) = 0
x.(2 + x) + 3x = 0

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     x(x+7)=0
    => \(\left[ \begin{array}{l}x=0\\x+7=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x=-7\end{array} \right.\) 
    vậy x∈{0, -7}
    (x+12)(x-3)
    => \(\left[ \begin{array}{l}x+12=0\\x-3=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=-12\\x=3\end{array} \right.\) 
    vậy x∈{-12 ; 3 }
    (-5+x).(3-x)
    => \(\left[ \begin{array}{l}-x+5=0\\3-x=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}-x=-5\\x=3\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\) 
    Vậy x∈{5;3}
    x.(2 + x) + 3x = 0
    => x.(2+x+3)=0
    => x.(5+x)=0
    => \(\left[ \begin{array}{l}x=0\\5+x=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x=-5\end{array} \right.\) 
    vậy x∈{0;-5}

  2. Giải đáp + Lời giải và giải thích chi tiết:
     a, x(x+7)=0
    <=> \(\left[ \begin{array}{l}x=0\\x+7=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x=-7\end{array} \right.\) 
    Vậy x=0;x=-7
    b, (x+12)(x-3)=0
    <=> \(\left[ \begin{array}{l}x+12=0\\x-3=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=-12\\x=3\end{array} \right.\) 
    Vậy x=-12;x=3
    c, (-x+5)(3-x)=0
    <=> \(\left[ \begin{array}{l}-x+5=0\\3-x=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\) 
    Vậy x=5;x=3
    d, x(2+x)+3x=0
    <=> 2x +x^2+3x=0
    <=> x^2+5x =0
    <=> x(x+5)=0
    <=> \(\left[ \begin{array}{l}x=0\\x+5=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x=-5\end{array} \right.\) 
    Vậy x=0;x=-5 

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222-9+11+12:2*14+14 = ? ( )