Toán Lớp 11: Làm giúp em với ạ
Khai triển nhị thức
(3x-4)^5
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Toán Lớp 11: Làm giúp em với ạ
Khai triển nhị thức
(3x-4)^5
Comments ( 2 )
$\left(3x-4\right)^5$
=(3x−4)*(3x−4)*(3x−4)*(3x−4)*(3x−4)
=243 x^5 – 1620 x^4 + 4320 x^3 – 5760 x^2 + 3840 x – 1024
$\text{$(3x – 4)^{5}$ }$
$\text{= 5C0.$3x^{5}$ – 5C1.$3x^{4}$.4 + 5C2.$3x^{3}$.4² }$
$\text{ – 5C3.$3x^{2}$.$4^{3}$ + 5C4.3x.$4^{4}$ – 5C5.$4^{5}$ }$
$\text{= 243$x^{5}$ – 1620$x^{4}$ + 4320$x^{3}$ – 5760$x^{2}$ }$
$\text{ + 3840x – 1020}$