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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Giải pt: cos2x-√3sin2x=2cosx giúp m với :((((

Toán Lớp 11: Giải pt: cos2x-√3sin2x=2cosx
giúp m với :((((

Comments ( 2 )

  1. $cos2x-\sqrt{3}sin2x=2cosx$
    $⇔2cos\bigg(2x+\dfrac{π}{3}\bigg)=2cosx$
    $⇔$\(\left[ \begin{array}{l}2x+\dfrac{π}{3}=x+k2π\\2x+\dfrac{π}{3}=-x+k2π\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}x=-\dfrac{π}{3}+k2π\\x=-\dfrac{π}{9}+k\dfrac{2π}{3}\end{array} \right.\) 
    $(k\in\mathbb{Z})$

  2. $\begin{array}{l}
    \cos 2x – \sqrt 3 \sin 2x = 2\cos x\\
     \Leftrightarrow 2\left( {\dfrac{1}{2}\cos 2x – \dfrac{{\sqrt 3 }}{2}\sin 2x} \right) = 2\cos x\\
     \Leftrightarrow \cos \dfrac{\pi }{3}\cos 2x – \sin \dfrac{\pi }{3}\sin 2x = \cos x\\
     \Leftrightarrow \cos \left( {2x + \dfrac{\pi }{3}} \right) = \cos x\\
     \Leftrightarrow \left[ \begin{array}{l}
    2x + \dfrac{\pi }{3} = x + k2\pi \\
    2x + \dfrac{\pi }{3} =  – x + k2\pi 
    \end{array} \right.\\
     \Leftrightarrow \left[ \begin{array}{l}
    x =  – \dfrac{\pi }{3} + k2\pi \\
    x =  – \dfrac{\pi }{9} + \dfrac{{k2\pi }}{3}
    \end{array} \right.\left( {k \in \mathbb Z} \right)
    \end{array}$

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222-9+11+12:2*14+14 = ? ( )